0=-16t^2-7t+50

Solution for 0=-16t^2-7t+50 equation:

0=-16t^2-7t+50

We move all terms to the left:

0-(-16t^2-7t+50)=0

We add all the numbers together, and all the variables

-(-16t^2-7t+50)=0

We get rid of parentheses

16t^2+7t-50=0

a = 16; b = 7; c = -50;
Δ = b2-4ac
Δ = 72-4·16·(-50)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-57}{2*16}=\frac{-64}{32}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+57}{2*16}=\frac{50}{32}
=1+9/16
$